(x^3+4x-3x+7)(x^2-5)=0

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Solution for (x^3+4x-3x+7)(x^2-5)=0 equation:


Simplifying
(x3 + 4x + -3x + 7)(x2 + -5) = 0

Reorder the terms:
(7 + 4x + -3x + x3)(x2 + -5) = 0

Combine like terms: 4x + -3x = 1x
(7 + 1x + x3)(x2 + -5) = 0

Reorder the terms:
(7 + 1x + x3)(-5 + x2) = 0

Multiply (7 + 1x + x3) * (-5 + x2)
(7(-5 + x2) + 1x * (-5 + x2) + x3(-5 + x2)) = 0
((-5 * 7 + x2 * 7) + 1x * (-5 + x2) + x3(-5 + x2)) = 0
((-35 + 7x2) + 1x * (-5 + x2) + x3(-5 + x2)) = 0
(-35 + 7x2 + (-5 * 1x + x2 * 1x) + x3(-5 + x2)) = 0
(-35 + 7x2 + (-5x + 1x3) + x3(-5 + x2)) = 0
(-35 + 7x2 + -5x + 1x3 + (-5 * x3 + x2 * x3)) = 0
(-35 + 7x2 + -5x + 1x3 + (-5x3 + x5)) = 0

Reorder the terms:
(-35 + -5x + 7x2 + 1x3 + -5x3 + x5) = 0

Combine like terms: 1x3 + -5x3 = -4x3
(-35 + -5x + 7x2 + -4x3 + x5) = 0

Solving
-35 + -5x + 7x2 + -4x3 + x5 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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